1.

`2H_(2)OhArrH_(3)O^(+)+OH^(-)` `K_(w)=1xx10^(-14)` at `25^(@)C`. Hence, `K_(a)` is:A. `1xx10^(-14)`B. `5.55xx10^(-13)`C. `1.8xx10^(-16)`D. `1.00xx10^(-7)`

Answer» Correct Answer - C
`K_(w)=[H^(+)][OH^(-)]=1xx10^(-14)`
`:. [H^(+)]=1xx10^(-7) M`,
`C= 1g//mL=1000 g//L=55.55 M`
Also in weak acid `[H^(+)]=sqrt(K_(a)C)`
`:. K_(a)=([H^(+)]^(2)]/(C )=(10^(-14))/(55.55)=1.8xx10^(-16)`


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