2whire nCestonkvelocit

1.	2whire nCestonkvelocit
Answer» λ= h/mv [de-Broglie wavelength] From E = hv [Plank's equation] h = E/v Write the dimension of each quantity in the above relation λ = wavelength = [L] , h = Energy / frequency = Energy x time = [ML2T-2][T] = [ML2T-1] mv = mass x velocity = momentum = [MLT-1] -- LHS = [L] RHS = [ML2T-1] / [MLT-1] = [L] We see that dimensions of both sides are equal to [L] The given relation is correct. λ= h/mv [de-Broglie wavelength] From E = hv [Plank's equation] h = E/v Write the dimension of each quantity in the above relation λ = wavelength = [L] , h = Energy / frequency = Energy x time = [ML2T-2][T] = [ML2T-1] mv = mass x velocity = momentum = [MLT-1] -- LHS = [L] RHS = [ML2T-1] / [MLT-1] = [L] We see that dimensions of both sides are equal to [L] The given relation is correct.

Answer»

λ= h/mv [de-Broglie wavelength]

From E = hv [Plank's equation]

h = E/v

Write the dimension of each quantity in the above relation

λ = wavelength = [L] ,

h = Energy / frequency = Energy x time = [ML2T-2][T] = [ML2T-1]

mv = mass x velocity = momentum = [MLT-1]

LHS = [L]

RHS = [ML2T-1] / [MLT-1] = [L]

We see that dimensions of both sides are equal to [L]

The given relation is correct.