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. 3.24 x 10-4 J of work is done in taking 3.0 x 10°C of charge in a uniform electric field from one point tothe other. If the distance between the points be 12 cm,calculate the intensity of the electric field.Ans. 9.0 x 104 V-m-1​

Answer»

ty of the electric field = 9 * 10^4 N/CExplanation:Given:  Work w = 3.24 * 10^-4 J CHARGE q = 3.0 * 10^-8  C radius R = 12 cm = 0.12 MFIND: Intensity of the electric field Solution: w = qvWhere w is the work, q is the charge and v is the potential in volts. Therefore v = w/q But we know that E = v / r = w/ qr = 3.24 * 10^-4 / (3.0 * 10^-8  *  0.12 )     = 9 * 10^4 N/C



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