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3.8 < x < 4.8 Express in modulus and neighbourhood form

Answer»

Here, a – δ = 3.8; a + δ = 4.8

By adding, 2a = 8.6

∴ a = \(\frac{8.6}2\) = 4.3

Putting a = 4.3 in a + δ = 4.8,

4.3 + 8 = 4.8

∴ δ = 4.8 – 4.3 = 0.5

In Modulus form : | x – a| < δ
3.8 < x < 4.8 = |x – 4.31 < 0.5

In Neighbourhood form: N (a, δ)
3.8 < x < 4.8 = N (4.3, 0.5)



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