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3.) A 50 g ball hits a wall at an angle 45° with speed 20 m/s and rebounds with the same speedperpendicular to the direction of incidence. Find the impulseii) A car is moving with a speed x m/s can be stopped by a force in distance y, lf mass of the car isincreased by 50% what would be new stopping distance in terrms of y; force remaining sameOri) Find a vector whose magnitude is 10 and which is perpendicular to the vectors A-2i+3j-4k and |
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Answer» 3 I)Impulse I = change in momentum I= mv’-mv we will take vertival and horizontal component angle theta = 45’ I= (mvcos45°-mvsin45°)-(mvcos45°-mvsin45°) vertical resolution cancelout & horizontal adds up I=2mvsin45 I=2*0.05*20*1\root2 = 1\root2 = √2/2 N-s |
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