3. A body is projected horizontally from the top of a tower with initi

1.	3. A body is projected horizontally from the top of a tower with initial velocity 18 ms-1, It hits the ground at angle45 What is the vertical component of velocity when it strikes the ground?n) 9 ms-
Answer» If velocity of the body when It strikes the ground is v at an angle of 45°, then Horizontal component of v =Initial horizontal velocity It is because there is no force acting on the body horizontally and so velocity remains constant. Thus v Cos 45°=horizontal component of velocity at the point of strike=18 m/s The vertical component of the velocity=v Sin 45°=v Cos 45° (since Sin 45°=Cos 45°) Thus vertical component of velocity of the body at the point of strike=v Cos45° =18 m/s

3. A body is projected horizontally from the top of a tower with initial velocity 18 ms-1, It hits the ground at angle45 What is the vertical component of velocity when it strikes the ground?n) 9 ms-

Answer»

If velocity of the body when It strikes the ground is v at an angle of 45°, then

Horizontal component of v =Initial horizontal velocity

It is because there is no force acting on the body horizontally and so velocity remains constant. Thus

v Cos 45°=horizontal component of velocity at the point of strike=18 m/s

The vertical component of the velocity=v Sin 45°=v Cos 45° (since Sin 45°=Cos 45°)

Thus vertical component of velocity of the body at the point of strike=v Cos45°

=18 m/s

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3. A body is projected horizontally from the top of a tower with initial velocity 18 ms-1, It hits the ground at angle45 What is the vertical component of velocity when it strikes the ground?n) 9 ms-

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