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3. A man stationed between two parallel cliffs fires a gun. He hears the first echo after 1.5 s and the next after2.5 s. What is the distance between the cliffs and when does he hear the third echo? Take the speed of sound inair is 340 m/s. |
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Answer» Suppose the two cliffs are A and B which are at the distances x and y from the man respectively. Consider that the echo of 1.5 sec and 2.5 sec are produced by are produced by cliff A and B. 2x = 340 x 1.5 x = 255 m 2y = 340 x 2.5 y = 425 m Distance between the cliff = x + y = 680 m The third echo will be heard after 1.5 sec from the time when the second echo is heard. answer one more |
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