3.i) A 50 g ball hits a wall at an angle 45° with speed 20 m/s and re

1.	3.i) A 50 g ball hits a wall at an angle 45° with speed 20 m/s and rebounds with the same speedperpendicular to the direction of incidence. Find the impulse.ii) A car is moving with a speed x m/s can be stopped by a force in distanceincreased by 50% what would be new stopping distance in terms of force remaining sameOrii) Find a vector whose magnitude is 10 and which is perpendicular to the vectors A-21+3)-4k andB-6i-9k+2j both.
Answer» Impulse I = change in momentum I= mv’-mv we will take vertival and horizontal component angle theta = 45’ I= (mvcos45°-mvsin45°)-(mvcos45°-mvsin45°) vertical resolution cancelout & horizontal adds up I=2mvsin45 I=20.0520*1\root2 = 1\root2 = √2/2

3.i) A 50 g ball hits a wall at an angle 45° with speed 20 m/s and rebounds with the same speedperpendicular to the direction of incidence. Find the impulse.ii) A car is moving with a speed x m/s can be stopped by a force in distanceincreased by 50% what would be new stopping distance in terms of force remaining sameOrii) Find a vector whose magnitude is 10 and which is perpendicular to the vectors A-21+3)-4k andB-6i-9k+2j both.

Answer»

Impulse I = change in momentum

I= mv’-mv

we will take vertival and horizontal component

angle theta = 45’

I= (mvcos45°-mvsin45°)-(mvcos45°-mvsin45°)

vertical resolution cancelout & horizontal adds up

I=2mvsin45

I=2*0.05*20*1\root2

= 1\root2

= √2/2

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