3. YA projectile is fired at an angle of 60Â° to the horizontal with

1.	3. YA projectile is fired at an angle of 60Â° to the horizontal with an initial velocity of 800 m/s;i) Find the time of flight of the projectile before it hits the groundii) Find the distance it travels before it hits the ground (range)iii) Find the time of flight for the projectile to reach its maximum height.
Answer» Answers-T = 1384 sR = 27712 mTa = 692 s Explaination------------------------Given-u = 800m/sθ = 60° Solution-a) Time of flight-T = 2usinθ/gT = 2×800×sin60T = 1384 s b) Horizontal range,R = u^2sin2θ/2gR = 800^2 × sin120 / (2×10)R = 32000×0.866R = 27712 mR = 27 km c) Time of ascent-Ta = usinθ/gTa = 800×sin60Ta = 692 s

3. YA projectile is fired at an angle of 60Â° to the horizontal with an initial velocity of 800 m/s;i) Find the time of flight of the projectile before it hits the groundii) Find the distance it travels before it hits the ground (range)iii) Find the time of flight for the projectile to reach its maximum height.

Answer»

Answers-T = 1384 sR = 27712 mTa = 692 s Explaination------------------------Given-u = 800m/sθ = 60°

Solution-a) Time of flight-T = 2usinθ/gT = 2×800×sin60T = 1384 s

b) Horizontal range,R = u^2sin2θ/2gR = 800^2 × sin120 / (2×10)R = 32000×0.866R = 27712 mR = 27 km

c) Time of ascent-Ta = usinθ/gTa = 800×sin60Ta = 692 s

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