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30. A brick has 3 sides a, b.c fa> b> c). The brick can be kept on ground on any face. The work required ndone to move from minimum potential energy to maxir m potential energy is:(A) mg(a/2-b/2)(3 ) (B) mg(a/2-c/2 )(C) mg(b/2-a/2)(D) mg(a+c/2-b/2) |
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Answer» Maximum potential energy is obtained with the brick vertical along side a=mga/2 Minimum potential energy is obtained with the brick vertical along side c=mgc/2 :. Work done=mg(a/2-c/2) Hence, option (B) is correct. |
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