1.

30. A brick has 3 sides a, b.c fa> b> c). The brick can be kept on ground on any face. The work required ndone to move from minimum potential energy to maxir m potential energy is:(A) mg(a/2-b/2)(3 ) (B) mg(a/2-c/2 )(C) mg(b/2-a/2)(D) mg(a+c/2-b/2)

Answer»

Maximum potential energy is obtained with the brick vertical along side a=mga/2

Minimum potential energy is obtained with the brick vertical along side c=mgc/2

:. Work done=mg(a/2-c/2)

Hence, option (B) is correct.



Discussion

No Comment Found

Related InterviewSolutions