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30.A car of mass 1000 kg moves on a circular pathwith constant speed of 16 m/s. It is turned by 90°after travelling 628 m on the road. The centripetalforce acting on the car is-(A) 160 N(C) 640 MN(B) 320 NN(D) 1280 N

Answer»

We know that, s=rθ

Since it changes its direction after travelling 628m. Using the above formula, 628=r(π/2).

Solving further we get, r=400

Now centripetal force= mv2/r

Further substituting the value of r above we get1000*16*16/400=640N



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