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30 moles of PCl_(5) are placed in a 2 L reaction vessel and heated. K_(c ) for the reaction is 0.5. What is the composition of the mixture at equilibrium ? PCl_(5) hArr PCl_(3)+Cl_(2) |
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Answer» Solution :`(i) K_(c )=([HI]^(2))/([H_(2)][I_(2)])` `K_(c )=(["Products"]^("COEFFICIENTS"))/(["Reactants"]^("coefficients"))` (ii) calculation of concentration of the reactants and products at EQUILIBRIUM (iii) 5 MOLES of `PCl_(3)`, 5 moles of `Cl_(2)` and 25 moles of `PCl_(5)` |
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