32. Water is flowing at a speed of 1.Sms through horizontal tube of cr

1.	32. Water is flowing at a speed of 1.Sms through horizontal tube of cross - sectional area10 ms and you are trying to stop the flow by your palm Assuming that the waterstops immediately after hitting the palm the mininmum force that you must exert shoadbe (density of water-10kg)1) 15N2) 22.5N3) 33.7N4) 45N
Answer» Since the water attains zero velocity immediately after impact with palm , the force acting on it will be (Density)(Area) [(velocity)^2] because this is actually the momentum of the water flowing per second, which is actually force. I was able to write this because AreaxVelocity is Quantity of Water flowing per second. Multiply this by Density , you get Mass of water flowing per second. Multiply this by velocity and you get momentum flowing per second. You can check that the dimensions of this formula have the same dimensional formula as that of force. Now putting the values, we obtain the answer b.) 22.5 N

32. Water is flowing at a speed of 1.Sms through horizontal tube of cross - sectional area10 ms and you are trying to stop the flow by your palm Assuming that the waterstops immediately after hitting the palm the mininmum force that you must exert shoadbe (density of water-10kg)1) 15N2) 22.5N3) 33.7N4) 45N

Answer»

Since the water attains zero velocity immediately after impact with palm , the force acting on it will be (Density)(Area) [(velocity)^2] because this is actually the momentum of the water flowing per second, which is actually force.

I was able to write this because AreaxVelocity is Quantity of Water flowing per second. Multiply this by Density , you get Mass of water flowing per second. Multiply this by velocity and you get momentum flowing per second. You can check that the dimensions of this formula have the same dimensional formula as that of force.

Now putting the values, we obtain the answer b.) 22.5 N

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