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33.A body starts from rest and moves with an acceleration of 2m/s. Find thedistance travelled by the body in 5th second.a) 9mb) 2.5mc) 4.5md) 25m |
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Answer» Distance covered in nth second is given bys = u + 1/2 a (2n - 1) Here,u = 0,a = 2 m/s^2n = 5 Therefore,Distance covered in 5th second= 0 + 1/2 * 2(2*5 - 1)= 10 - 1= 9 m (a) is correct option |
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