Saved Bookmarks
| 1. |
34.Num. Determine the acceleration of the Jeep.A racing cur accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine theacceleration of the car and the distance traveled. |
|
Answer» V=46.1m/sU=18.5m/sT=2.47 secV=u+at46.1=18.5+a*2.472.47a=46.1-18.5=27.6a=27.6/2.47==11.17m/sec^2Distance=ut+.5at^2 =(18.5*2.47)+(0.5*11.47*2.47*2.47)=45.695+34.99=80.68m it's answer can be found by 2nd equation of motions=ut+1/2at^2 |
|