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34.તો આ અતર S નું મૂર્વ રીપી. 9 TUITIA body falling for 2 seconds covers a distance S equal tothat covered in next second. Taking g=10m/sS-[EAMCET (Engg.) 1995)(a) 30 m(b) 10 m(c) 60 m(d) 20 m |
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Answer» distance travelled by the body in 2 seconds is,s=ut+12gt2 =u×2+12×g×2×2 =2u+2g (i)Distance travelled by the body in next second is,s=u+g22n-1 =u+g22×3-1 =u+5g2 (ii)Since, the body covers equal distance, so from equation (i) and (ii), 2u+2g=u+5g2 or, u=g2 Now putting the value of u in equation (i), we get, s=2u+2g =2×g2+2g =3g=3×10=30 m . option a is correct answer --- I hope it helps u |
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