1.

35. A body with intial velocity u, is moving withuniform acceleration 'a', along a straight line.The sum of the distances travelled by it in thetth and (t+1)th seconds is 80 m. What is itsvelocity at the end of th second ?40 m/s (2) 55 m/s (3) 30 m/s (4) 50 m/s1I. wot t the ton of a smooth

Answer»

The distance covered in 'Tth' second will be given as

s = u + (f/2).(2T - 1)

and

the distance covered in '(T+1)th' second will be given as

s' = u + (f/2).[2(T+1) - 1]

and we are given

if the sum of the distances travelled in Tth& ( T+1)thsec is 80m

so,

s + s' = 80m

or

u + (f/2).(2T - 1) +u + (f/2).[2(T+1) - 1] = 80m

or

2u + (f/2).[(2T - 1) + (2T + 2 - 1)] = 80m

or

2u + (f/2).[4T] = 80

or

2u + 2fT = 80

or

u + fT = 40

now, we know that

final velocity is given as

v = u + at

or in this case

v = u + fT

so,

we get the final velocity as

v = 40 m/s


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