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36 At what altitude (h) above the earth's surface wouldthe acceleration due to gravity be one fourth of itsvalue at the earth's surface?(2) h 4R(4) h 16R(3) h 2R37 If the gravitational force between two objects wereproportional to 1/R (and not as 1/R), where R lthe distance between them, then a particle inacircular path (under such a force) would have itsorbital speed v, proportional to(2) R° (independent of R)(3) 2 |
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Answer» 36)For this question, We have the formula,g'= g/(1+h/R)^2 Here g' = acceleration due to gravity at the height g = 9.8m/s^2 R = radius of earth h = height g/g' = (1+h/R)^2 4 = (1+h/R )^2 1+h/R = 2 h/R = 1 h = R |
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