1.

36g of glucose (molar mass = `180 g//mol)` is present in 500g of water, the molarity of the solution isA. 0.2B. 0.4C. 0.8D. 1

Answer» Correct Answer - B
Molarity `= (W xx 1000)/(M xx W)`
where V = volume of water `= 500 mL`
W = mass of glucose `= 36g`
M = mol mass of glucose `= 180 g mol^(-1)`
Molarity `= (36 xx 1000)/(180 xx 500) = 0.4M`


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