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36g of glucose (molar mass = `180 g//mol)` is present in 500g of water, the molarity of the solution isA. 0.2B. 0.4C. 0.8D. 1 |
Answer» Correct Answer - B Molarity `= (W xx 1000)/(M xx W)` where V = volume of water `= 500 mL` W = mass of glucose `= 36g` M = mol mass of glucose `= 180 g mol^(-1)` Molarity `= (36 xx 1000)/(180 xx 500) = 0.4M` |
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