3b5. The displacement of the particle is given by y a+brtct -dt4. The

1.	3b5. The displacement of the particle is given by y a+brtct -dt4. The initial velocity and acceleration arerespectively(A) b,-4d(B) -b,2c(D) 2c,-4d
Answer» Displacement as function of time is given. y=a+ bt+ ct^2 + dt^4…………….(1) The time derivative of displacement or time rate of change of displacement gives velocity. Therefore, differentiating equation (1) w r t time, we get, velocity,v=dy/dt=b + 2ct +4dt^3…………..(2) To find velocity at t=0, we put t=0 in equation (2). Then, v( at t = 0)= b……………..(3) The time derivative of velocity gives acceleration. Therefore, differentiating equation (2) wrt time, we get, dv/dt = a( acceleration)= 2c + 12 dt^2…………..(4).

3b5. The displacement of the particle is given by y a+brtct -dt4. The initial velocity and acceleration arerespectively(A) b,-4d(B) -b,2c(D) 2c,-4d

Answer»

Displacement as function of time is given.

y=a+ bt+ ct^2 + dt^4…………….(1)

The time derivative of displacement or time rate of change of displacement gives velocity. Therefore, differentiating equation (1) w r t time, we get,

velocity,v=dy/dt=b + 2ct +4dt^3…………..(2)

To find velocity at t=0, we put t=0 in equation (2). Then,

v( at t = 0)= b……………..(3)

The time derivative of velocity gives acceleration. Therefore, differentiating equation (2) wrt time, we get,

dv/dt = a( acceleration)= 2c + 12 dt^2…………..(4).

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