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(4) 14A bullet of mass m passes through a pendulum bob of mass M with velocity v and comes out of t wih aelocity . The minimum value of v so that the bob completes one revolution in the vertical circles= length of pendulum)2Mg/(7m2M(4) v5g |
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Answer» Using Conservation of momentuminitial momentum = mv final momentum = M√5gl + mv/2 mv=M√5gl +mv/2 mv - mv/2 =M√5gl mv/2 = M√5gl v=(2M√5gl )÷m V = 2(M/m)√5gl option 3 thanks ma'am |
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