1.

4 charges are placed each at a distance 'a' from origin. The dippie snoment ofconfiguration is3q2q-2q

Answer»

all four charges are placed , each at a distance 'a ' from the origin.it means distance between two charges = √{a² + a² } = √2a

we also know, dipole moment is the system of two equal magnitude but opposite nature charges . so, we have to divide the charges as shown in figure for making dipole .

hence, there are three dipoles form. Let P = q(√2a) then, P₁ = P , P₂ = P and P₃ = 2P {as shown in figure.} now resolve the vectors P₁ ,P₂ and P₃ .

as shown in figure, vertical components of P₁ and P₂ is cancelled .and horizontal components of P₁ and P₂ is cancelled by horizontal component of P₃ .and rest part of dipole = vertical component of P₃ = 2Psin45° j ['j' shows direction of net dipole moment]hence, net dipole moment = 2q(√2a) × 1/√2 j = 2qa j



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