InterviewSolution
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InterviewSolution
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4 If a body starts from rest and travels 120 cm in the 6th second, then what is the acceleration(1) 0.20 ms2 (2) 0.027 ms-2(3) 0.218 ms2(4) 0.03 ms-2 |
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Answer» If we assume constant acceleration then s=ut+0.5at^2 where s is distance, u is initial velocity and t is time. In this instance I will call distance at 5 seconds s5, and at 6 seconds s6. We know that s6-s5= 1.2m (using metres to be consistent throughout) s5=ut+0.5at^2 , t=5, u=0 so… s5=0.5*a*25=12.5a and s6=ut+0.5at^2, t=6, u=0 s6=18a so now we know that s6=18a, s5=12.5a and s6-s5=1.2 from this we can work out that 5.5a=1.2 and therefore a=1.2/5.5 Acceleration is 0.218 ms^-2 |
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