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4. In fig. it is giverfig, it is given that AE = AD andRDCE. Prove that A AEB = A ADC

Answer»

In ΔAEB and ΔADC AE = AD (Given) ∠EAB = ∠DAC (common) AB = AC { :- AE = AD and EC = BD }

thus

Δ AEB ≈ ΔADC (SAS congurency)

Given, AE=ADBD=CEIn Δ AEB and ADC AE=AD(Given) Angle EAB = Angle DAC (Common) BD=CE(Given)ΔAEB is congruent to ADC (By SAS)

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