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4.) In Millikan's experiment, an oil drop of radius10-4 cm remains suspended between the plateswhich are 1 cm apart. If the drop has charge of 5eover it, calculate the potential difference betweenthe plates. The density of oil may be taken as1.5 gcm |
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Answer» Since, the radius is 1.64 mm i.e. r = 1.64 x 10-6m As we know, m=∂*v (where∂ is density and v is volume) therefore, m = 0.851 x 4/3-pi-r3 = 1.45 x 10-17kg We have already studued that qE= mg q=mg/E =1.45 x 10-17 x9.8/1.92x 105 = 7.4 x 10-22C . |
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