1.

4.) In Millikan's experiment, an oil drop of radius10-4 cm remains suspended between the plateswhich are 1 cm apart. If the drop has charge of 5eover it, calculate the potential difference betweenthe plates. The density of oil may be taken as1.5 gcm

Answer»

Since, the radius is 1.64 mm

i.e. r = 1.64 x 10-6m

As we know, m=∂*v

(where∂ is density and v is volume)

therefore, m = 0.851 x 4/3-pi-r3

= 1.45 x 10-17kg

We have already studued that qE= mg

q=mg/E

=1.45 x 10-17 x9.8/1.92x 105

= 7.4 x 10-22C .



Discussion

No Comment Found

Related InterviewSolutions