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4.Resistance of a metal wire oflength 2 m is 35 Ί at 30°C. If the diameter of the wire is0.4 mm, what will be the resistivity of the metal at that temperature?

Answer»

Explaination-# Given-R = 35 ohmL = 2 mr = 0.4 mm = 4×10^-4 mT = 30 °C

# Solution-Resistivity of the material is given by the formula - ρ = RA / Lρ = Rπr^2 / Lρ = 35×3.142×(4×10^-4)^2 / 2ρ = 8.8×10^-6 ohm-m.

Therefore, resistivity of given metal wire at 30 °C is 8.8×10^-6 ohm-m.

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