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4) The average velocity of freely falling body is 21 ms-1. Then it is released from a height equal toa)5m b) 90m c) 30md) 60m |
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Answer» ANSWER : As the object is FREE falling, so, u=0, given, v-u=21, therefore, v=21. Hence, u=v+at (a is acceleration DUE to gravity) 0=21+9.8*t => t=-21/9.8= 2.15 approx. Now, s=it+1/2at^2 => s=0+1/2*(2.15)^2*9.8 l THINK you can MAKE it after this... Thanks |
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