4. Two tall buildings are situated 200 m apart. Withwhat speed must a

1.	4. Two tall buildings are situated 200 m apart. Withwhat speed must a ball be thrown horizontallyfrom the window 540 m above the ground in onebuilding, so that it will enter a window 50 m abovethe ground in the other(Ans. 20 ms-)
Answer» Vertical distance between the two buildings = 540 – 50 = 490m Horizontal distance = 200 m Suppose ball speed is u and time taken to reach the point is t so Ball has no initial velocity and takes time t for 490 meter so S = ut + ½ at^2 490 = 0 + ½ (9.8)(t^2) T = 10 sec Horizontal component remain same so we use x = ut 200 = u ( 10 ) U = 10 Ball will be thrown at a speed of 10 m / s

4. Two tall buildings are situated 200 m apart. Withwhat speed must a ball be thrown horizontallyfrom the window 540 m above the ground in onebuilding, so that it will enter a window 50 m abovethe ground in the other(Ans. 20 ms-)

Answer»

Vertical distance between the two buildings = 540 – 50 = 490m

Horizontal distance = 200 m

Suppose ball speed is u and time taken to reach the point is t so

Ball has no initial velocity and takes time t for 490 meter so

S = ut + ½ at^2

490 = 0 + ½ (9.8)(t^2)

T = 10 sec

Horizontal component remain same so we use x = ut

200 = u ( 10 )

U = 10

Ball will be thrown at a speed of 10 m / s

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4. Two tall buildings are situated 200 m apart. Withwhat speed must a ball be thrown horizontallyfrom the window 540 m above the ground in onebuilding, so that it will enter a window 50 m abovethe ground in the other(Ans. 20 ms-)

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