1.

40 mL of alcohol is mixed with 160 mL of water.

Answer»

SOLUTION :VOLUME of alcohol (solute) = 40 mL
Volume of water (solvent) = 160 mL
`THEREFORE` Volume of solute + Volume of solvent
= 40mL + 160 mL = 200 mL
Percentage of concentration of solution,
`(%v//v)=("Volume of solute")/("Volume of solution")XX100`
= `40/200xx100=20%`


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