4142 K4 mole8) 2linder of fixed capacity 67.2 ltres contains heilumSTP

1.	4142 K4 mole8) 2linder of fixed capacity 67.2 ltres contains heilumSTP. Calculate the amount of heat required togas e temperature of the gas by 150C? (R-8.314 sraiseJ mo J 2)570.9 J 3)580.9J 4)590.9 J1) 561
Answer» Volume V = 67.2 litres of Helium at STP ΔT = 15⁰K1 mole of an ideal gas occupies 22.4 litres at STP. So number of moles of Helium gas n = 67.2/22.4 = 3 we know that γ = ratio of specific heats for an ideal mono atomic gas = 5/3 C_p = heat capacity at constant pressure for a mono atomic gas = 5/2 R C_v = heat capacity at constant volume for a mono atomic gas = 3/2 R Change in internal energy = n C_v ΔT = 3 * 3/2 * 8.31 J/mol/°K * 15°K = 560.925 Joules There is no change in the volume and hence no work done in heating the gas by 15 deg. Heat supplied = change in internal energy = 560.925 Joules

4142 K4 mole8) 2linder of fixed capacity 67.2 ltres contains heilumSTP. Calculate the amount of heat required togas e temperature of the gas by 150C? (R-8.314 sraiseJ mo J 2)570.9 J 3)580.9J 4)590.9 J1) 561

Answer»

Volume V = 67.2 litres of Helium at STP

ΔT = 15⁰K1 mole of an ideal gas occupies 22.4 litres at STP. So number of moles of Helium gas n = 67.2/22.4 = 3

we know that γ = ratio of specific heats for an ideal mono atomic gas = 5/3 C_p = heat capacity at constant pressure for a mono atomic gas = 5/2 R C_v = heat capacity at constant volume for a mono atomic gas = 3/2 R

Change in internal energy = n C_v ΔT = 3 * 3/2 * 8.31 J/mol/°K * 15°K = 560.925 Joules

There is no change in the volume and hence no work done in heating the gas by 15 deg.

Heat supplied = change in internal energy = 560.925 Joules

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