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45.A body is thrown from the surface of the earth with a speed of NGMIR (R -WİM = mass of earth). It rises to a maximum height of:c) 4Rradius anda) R/2b) Rd) 2R

Answer»

E2=(1/2)mv^2-GMm/R………..(2).

Now, E1=E2 ( conservation of energy). Therefore ,

-GMm/2R=(1/2)mv^2-GMm/R

OR (1/2)mv^2=GMm/2R, therefore ,

v=( GM/R)^1/2

this is case when R=2R



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