1.

46.A1.2 cm long pin is placed perpendicular to theprincipal axis of a convex mirror of focal length 12cm, at a distance of 8 cm from it. Find the height ofthe image?

Answer»

h1 = +1.2 cmf = +12 cmu = -8 cm

Using mirror formula ;

(1/f) = (1/v) + (1/u)

(1/12) = (1/v) + (1/-8)

1/v = (1/12) + (1/8)

1/v = (2+3)/24

v = 24/5

v = +4.8 cm======================

m = h2/h1 = -v/u

h2 = (-4.8/-8) × 1.2

h2 = + 0.72 cm___________________Hence the image formed is Virtual and erect of size 0.72 cm and at a distance of 4.8 cm from the mirror.



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