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46.A1.2 cm long pin is placed perpendicular to theprincipal axis of a convex mirror of focal length 12cm, at a distance of 8 cm from it. Find the height ofthe image? |
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Answer» h1 = +1.2 cmf = +12 cmu = -8 cm Using mirror formula ; (1/f) = (1/v) + (1/u) (1/12) = (1/v) + (1/-8) 1/v = (1/12) + (1/8) 1/v = (2+3)/24 v = 24/5 v = +4.8 cm====================== m = h2/h1 = -v/u h2 = (-4.8/-8) × 1.2 h2 = + 0.72 cm___________________Hence the image formed is Virtual and erect of size 0.72 cm and at a distance of 4.8 cm from the mirror. |
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