InterviewSolution
| 1. |
46. Solve the numerical given below: * (2 Points) A piece of metal of volume 30 cm has a mass of 252 9. Find the density of the meid 84 g/cm O 8.4 g/cm 8.4 kg/m 3 840 g/cm 47. Which of the following values can displacement have? (1 Point |
|
Answer» Answer: Solution: mass M of the piece of BRASS = 252 g Volume of the piece of volume = 30\ cm^330 cm
(i) density d = \frac{M}{V} V M
= \frac{252}{30}=8.4\ g\ cm^{-3} 30 252 =8.4 g cm −3
since, M = 252g = 0.252 KG V = 30\ cm^330 cm 3
= 30\times10^{-6}\ m^{-3}30×10 −6 m −3
Density d = \frac{0.252\ kg}{30\times10^{-6}\ m^{-3}}=\frac{0.252\ kg}{30\times\frac{1}{1000000}m^{-3}} 30×10 −6 m −3
0.252 kg = 30× 1000000 1 m −3
0.252 kg
= \frac{0.252\times1000000\ kg}{30\ m^3}=\frac{25200}{3}kg\ m^{-3}\ =\ 8400\ kg\ m^{-3} 30 m 3
0.252×1000000 kg = 3 25200 kg m −3 = 8400 kg m −3 HOPE IT WILL BE HELP YOU MARK ME AS A BRAINLIST |
|