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46. Steam at 100°C is passed into 22 grams ofwater at 20°C. When resultant temperature is90°C, then weight of the water present is1) 27.33 g2) 24.8 g3) 2.8 g4) 30 g |
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Answer» Answer: The weight of the water present is 24.8 gExplanation: LET the mass of steam CONDENSED be m. The heat released by steam is sum of heat released while condensing form stem to ice and heat released while TEMPERATURE is dropped from 100°C to 90°C. So, Q₁ = (m×L) + (m×(100−90)×1)⇒ Q₁ = 540 m + 10 m ⇒ Q₁ = 550 mHeat absorbed by 22 g of water to increase its temperature from 20°C to 90°C is : Q₂ = 22 × (90−20) × 1 ⇒ Q₂ = 1540 calEquating the two heats, m = 1540/550 ⇒ m = 2.8 gSo, Total mass = 22+2.8 ⇒ Total Mass = 24.8 g |
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