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46*. The system shown in the figure is in equilibrium. The maximum value of45100kgW, so that the maximum value of static frictional force on 100 kg. bodyis 450 N, will be:-(1) 100 N(2) 250 N(3) 450 N(4) 1000 N |
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Answer» Here the tension in the inclined string , will balance the horizontal and vertical movement of both the blocks so, vertical component of tension = Tcos(45°) = W and, horizontal component of tension =Tsin(45°)= friction force = 450 N upon dividing both the equation Tcos(45°)/Tsin(45°) = W/450 => W/450 = 1=> w = 450N option C |
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