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473Sample ProblemA small ink dot on a paper is viewed through a glass slab of thickness10 cm j and refractive index 1-5. By what distance would the dot appear to be raised?nckness of glass slab, x = 10 cm ; Îź = 1.5

Answer»

Refractive index of glass slab = (real thickness/ (apparent thickness )= 1.5

Real thickness = 10 cm

Therefore, apparent thickness = 10/1.5 = 20.0/3 = 6.66 cm

Therefore, the dot appears raised by = 10 cm - 6.66 cm = 3.34 cm height.



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