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48 similar cells each of emf 1.5 V and internal resistance 2 ohm are used for sending current through aresistance of 6 ohm. What will be the current if the cells are connected in the following way: (i) 6 rows and 8cells in a row, (ii) 4 rows and 12 cells in a row. |
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Answer» Answer: Emf of each cell (e) = 1.5V, internal resistance (r) = 2 ohm, external resistance (R) = 6 ohm. (i) No. of cells in a ROW (N) = 8 No. of ROWS (m) = 6
So, CURRENT, I = mne/mR + nr = 6×8×1.5/6×6+8×2 = 72/52 = 1.385 A (ii) No. of cells in a row (n) = 12 No. of rows (m) = 4
So, current, I = mne/mR+nr = 4×12×1.5/4×6+12×2 = 72/48 = 1.5 A |
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