1.

49. Two forces, each numericallyequal to 5 N, are acting asshown in the Fig. 6. Then theresultant is(a) 2.5 N5 N(b) 5 N(c) 5/3 N(d) 10 N.60°5 N

Answer»

upon moving The horizontal 5N force to connect with the tail

we get the angle as 180°-60° = 120°angle( __/ )

so, resultant is √5²+5²-2*5*5cos(120) = √5²+5²-5² = √5² = 5N



Discussion

No Comment Found

Related InterviewSolutions