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49. Two forces, each numericallyequal to 5 N, are acting asshown in the Fig. 6. Then theresultant is(a) 2.5 N5 N(b) 5 N(c) 5/3 N(d) 10 N.60°5 N |
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Answer» upon moving The horizontal 5N force to connect with the tail we get the angle as 180°-60° = 120°angle( __/ ) so, resultant is √5²+5²-2*5*5cos(120) = √5²+5²-5² = √5² = 5N |
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