1.

(5 + 13 + 21 + … + 181) = ? (a) 2476 (b) 2337 (c) 2219(d) 2139

Answer»

Correct answer is (d) 2139

Here, a = 5, d = (13 - 5) = 8 and l = 181

Let the number of terms be n.

Then, Tn = 181

\(\Rightarrow\) a + (n - 1) d = 181

\(\Rightarrow\) 5 + (n - 1)x8 = 181

\(\Rightarrow\) 8n = 184

\(\Rightarrow\) n = 23

∴ Required sum = \(\frac{n}{2}(a+l)\)

\(\frac{23}{2}(5+181)=23\times93=2139\)

Hence, the required sum is 2139.



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