InterviewSolution
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InterviewSolution
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5.6 liter of helium gas at STP is adiabatically compressed to 0.7 liter. Taking the initial temperature to be `T_1,` the work done in the process isA. `(9)/(8)RT_(1)`B. `(3)/(2)RT_(1)`C. `(15)/(8)RT_(1)`D. `(9)/(2)RT_(1)` |
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Answer» Correct Answer - A `W=(nR(T_(1)-T_(2)))/(r-1) T_(1) (5.6)^(2//3)=T_(2)(0.7)^(2//3)` `impliesT_(2)=T_(1)(8)^(2//3)` `=T_(1)xx4 W =(nRxx3T_(1))/(2//3)=(9)/(2) nRT_(1)` But `n =(1)/(4) implies W = (9)/(8)RT_(1)`. |
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