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5. A cylinder of diameter 1.0 cm at 30°C is to be slidinto a hole in a steel plate. The hole has a diameterof 0.99970 cm at 30°C. To what temperature mustthe plate be heated ? For steel, α 1.1x 10-5°C-1Ans, 5730 |
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Answer» ΔL=Lo(steel plate)α(steel plate)(Tf-To) 1.0cm-0.99970 cm = (0.99970 cm)(1.1x10^5)(Tf-30) Tf=57.28°C |
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