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5.Calculate the resistance of 50m length of wire of cross section area 0.01 millimetresquare and of resistivity 5x108 ohm meter?

Answer»

resistance is R = ρl/a

so , here ρ = 5*10^-8 and l = 50 , and a = 0.01mm² = 0.01*10⁻⁶ m²

so, R = (5*10^-8)*50/0.01*10^⁻⁶R = 250 Ω



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