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5) If the percentage and masssignificant figures.percentage error of measurement in velocity2% and 4% respectively, what is the percentage error in kinetic energy (k. E= 1/2 mv²)​

Answer»

8%EXPLANATION:Given percentage errors in mass and velocity = 2% and 3% respectivelyThe KINETIC energy of the particle is given by KE = 2MV 2 The percentage ERROR in kinetic energy will bemΔm ×100+2 vΔv ×100= 2+6= 8%



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