5. If the velocity of a train which starts from rest is 72 km/h (20 m/

1.	5. If the velocity of a train which starts from rest is 72 km/h (20 m/s)after 5 minute, find out its acceleration and the distance travelledby the train in this time.
Answer» Explanation: 5min=5×60=300s a=change in velocity/time a=20/300 1/15 s=ut +1/2at2 s=1/2×1/15×300×300 s=3000metre..

5. If the velocity of a train which starts from rest is 72 km/h (20 m/s)after 5 minute, find out its acceleration and the distance travelledby the train in this time.

Answer»

Explanation:

5min=5×60=300s

a=change in velocity/time

a=20/300

1/15

s=ut +1/2at2

s=1/2×1/15×300×300

s=3000metre..

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5. If the velocity of a train which starts from rest is 72 km/h (20 m/s)after 5 minute, find out its acceleration and the distance travelledby the train in this time.​

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5. If the velocity of a train which starts from rest is 72 km/h (20 m/s)after 5 minute, find out its acceleration and the distance travelledby the train in this time.