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,5.-The resistance R-V/1, where Y-(100ĺ5) V, I_ (10Âą0.2). Find the percentageerror in R. |
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Answer» v=(100+-5)a I=(10+-0.2)a R=V/I =100/10=10Ω ΔR/R=+_[ΔV/V+ΔI/I] =+_[5/100+0.2/10] =+_[7/100] =+_0.07 ΔR=R*0.07 =+_0.07*10 =0.7 ohms Percentage errorΔR/R*100=+_0.07*100=+_7 percent |
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