1.

,5.-The resistance R-V/1, where Y-(100土5) V, I_ (10±0.2). Find the percentageerror in R.

Answer»

v=(100+-5)a

I=(10+-0.2)a

R=V/I =100/10=10Ω

ΔR/R=+_[ΔV/V+ΔI/I]

=+_[5/100+0.2/10]

=+_[7/100]

=+_0.07

ΔR=R*0.07

=+_0.07*10

=0.7 ohms

Percentage errorΔR/R*100=+_0.07*100=+_7 percent



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