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5. Two masses mi = 5 kg and m2 = 4 kgtied to a string are hanging overlight frictionless pulley. What is theacceleration of each mass when left freeto move? (g = 10ms-2) |
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Answer» Net force acting on the system will be 5g -4g = (5-4)*10 = 10N now total mass of system = (5+4) + 9kg so, acceleration = F/m = 10/9 m/s². thank you! |
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