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`50 mL` of `10 N H_(2)SO_(4), 25 mL` of `12 N HCI` and `40 mL` of `5N HNO_(3)` are mixed and the volume of the mixture is made 1000 mL by adding water. The normality of resulting solution will beA. `1N`B. `2N`C. `3N`D. `4N` |
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Answer» Correct Answer - A `N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3)=N_(4)V_(2)` `10 N xx 50 mL +12 Nxx25 mL+5 Nxx40 mL` `=N_(4)xx1000 mL` (Volume of mixture = 1000 mL) `N_(4) = (500+300+200)/(1000) N = 1N` |
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