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500J work is required to carry charged particle between two points with potential difference of 20V. what is the magnitude of charge on particle? |
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Answer» ANSWER: According to Question Data Work required ΔU = 500J Potential DIFFERENCE ΔV =20 V Magnitude of Charge ? By using FORMULA ΔV = ΔU/Q or Q = ΔU/ΔV by putting values Q = 500/20 Q = 25 Coloumb |
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