1.

500J work is required to carry charged particle between two points with potential difference of 20V. what is the magnitude of charge on particle?

Answer»

ANSWER: According to Question

Data

Work required ΔU = 500J

Potential DIFFERENCE ΔV =20 V

Magnitude of Charge ?

EXPLANATION:

By using FORMULA

ΔV = ΔU/Q

or Q = ΔU/ΔV

by putting values

Q = 500/20

Q = 25 Coloumb



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