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52.4 J of work is required to stretch a spring through10 cm beyond its unstretched length. The extrawork required to stretch it through additional10 cm shall be(1) 4 J(3) 12 J(2) 8 J(4) 16 J |
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Answer» The potential energy in string stored is = 1/2*(k)(10)² => 4 = 1/2*(k)*100=> K = 4/50 now when string is stretched to further 10cm the equation is W = 1/2*(k)*(20²-10²)W = 1/2*(4/50)*(400-100)W = 300/25 = 12J. option 3. |
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