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53. In the given figurecalculate the equivalentcapacity between M NHand NAns. 2.4μF.Hint : Total capacityAF3F 4AF4×654. In the above přoblem calcylate the charge on each capacitor if p. d.across M and N is 120 volt.Ans, 72uC, 216uC, 96uC and 192uC.

Answer»

At first 1μF and 3μF are in parallel the add up to 4μF , also 2μF and 4μF are in parallel , so they add up to 6μF

now 4μF and 6μF are in series with each other..

so, the equivalent capacitance is = 4*6/(4+6) = 2.4μF

54 ka



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